Home Physics Newton's Laws of Motion Second Law of Motion A 4 kg block A is placed on the top of a 8 k…
Physics Newton's Laws of Motion Second Law of Motion MCQ (Single Correct)

A 4 kg block A is placed on the top of a 8 kg block B which rests on a smooth table. A just slips on B when a force of 12 N is applied on A. Then the maximum horizontal force on B to make both A and B move together, is

A
12 N
B
24 N
C
36 N
D
48 N

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Verified by Experts
The correct answer is:
C

Maximum friction i.e. limiting friction between A and B, = 12 N.

If F is the maximum value of force applied on lower body such that both body move together

It means Pseudo force on upper body is just equal to limiting friction

⇒ ⇒

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